Find the magnitude of the velocity of the block just after impact.?
A rifle bullet with a mass of 8 grams strikes and embeds itself in a block with a mass of 0.992 kg. The block rests on a frictionless horizontal surface and is attached to a spring. The impact compresses the spring by 15 cm. In a previous spring lab, students determined that a force of 0.75 N was required to stretch the spring by 0.25 cm.
A) What is the magnitude of the velocity of the block just after the impact?
B) What is the initial speed of the bullet?
1 Answers
Feb 13, 2025
A) The spring constant k is 0.75N / 0.25 cm (convert cm to m)
The spring potential energy at the compression of 15 cm (convert cm to m) is given by
(1/2)kx^2
That energy was converted from the block's initial kinetic energy. Remember, the block includes the 8 g bullet. Find the total mass. The principle of conservation of energy says
(1/2)kx^2 = (1/2)mv^2
Solve for v.
B) Use the principle of conservation of momentum for this
momentum before = momentum after
m1u1 + m2u2 = (m1+m2)*v
where u1 and u2 are the velocities of the bullet and block before the bullet hits the block. Solve for u1.
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