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Find the magnitude of the velocity of the block just after impact.?

A rifle bullet of mass 8 grams strikes and embeds itself in a block of mass0.992kg that rests on a frictionless horizontal surface and is attached to a spring. The impact compresses the spring 15 cm. In an earlier spring lab, students found that a force of 0.75N was required to stretch the spring 0.25 cm.A) Find the magnitude of the velocity of the block just after impact. B) What is teh initial speed of the bulelt?

1 Answers

A) The spring constant k is 0.75N / 0.25 cm (convert cm to m)The spring potential energy at the compression of 15 cm (convert cm to m) is given by(1/2)kx^2That energy was converted from the block's initial kinetic energy. Remember, the block includes the 8 g bullet. Find the total mass. The principle of conservation of energy says(1/2)kx^2 = (1/2)mv^2Solve for v.B) Use the principle of conservation of momentum for thismomentum before = momentum afterm1u1 + m2u2 = (m1+m2)*vwhere u1 and u2 are the velocities of the bullet and block before the bullet hits the block. Solve for u1.... Show More

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