Functions 1 and 2 are shown below: Function 1: f(x) = −4×2 + 6x + 3 ‘A graph of a parabola with x intercepts negative 1, 0 and 1,

Question

Functions 1 and 2 are shown below: 
Function 1: f(x) = −4x² + 6x + 3. 
The graph of this function is a parabola with x-intercepts at -1, 0, and 1, and a vertex at (0, 3). 
Which function has a larger maximum? Please type your answer as either 1 or 2. (2 points)

Miss Meaghan Dooley · Accepted Answer

2. i belive the answer should be

Anonymous · Answer

Function 2 has a larger maximum.Step-by-step explanation:The maximum is basically the ᴘᴇᴇk of the line on the graph. think of it like the ᴘᴇᴇk of a mountain. We already know the maximum of function two which is 4. but now we need to graph function 1 so we can compare. After you graph function one you will see that the ᴘᴇᴇk or the maximum on that line is at 2, which is less than 4. So that means Function 2 had a larger maximum.

Anonymous · Answer

B Step-by-step explanation:Function 2 has a larger maximum.

Anonymous · Answer

Doesn't function 2 have the larger maximum? When function 2 is graphed the maximum is at 4.

Anonymous · Answer

Functions g and h have the same maximum of 2.Step-by-step explanation:

Anonymous · Answer

its c for the last on and i dont know the firstStep-by-step explanation:

Tamia Moen · Answer

k= one halfStep-by-step explanation:

Anonymous · Answer

The function 2 has a larger maximum. Step-by-step explanation:The vertex form of the parabola is              .... (1)Where, (h,k) is the vertex.The given functions are                 ..... (2)Since the leading coefficient is negative, therefore it is a downward parabola. It means the vertex of the parabola is the maximum point.On comparing (1) and (2), we getTherefore the maximum value of the function is 2 at x=0. The second function has x intercepts of (-0.5, 0) and (2, 0) and a vertex of (0.5, 4).It is also a downward parabola because the parabola has two x-intercepts and the vertex lies above the x-axis.Since the vertex is (0.5, 4), therefore the maximum value of the function is 4 at x=0.5.Therefore function 2 has a larger maximum.

Anonymous · Answer

The maximum value of function 1 is 2 and  maximum value of function 2 is 4. So, function 2 has a larger maximum.Step-by-step explanation:In Function 1 : Lending coefficient is negative. It is a downward parabola and vertex is the maximum point.vertex of a parabola isOn comparing with given equation we ave; a = -3 , b=0 and c = 2then;Substitute the value of x =0 in we have;⇒Vertex = (0, 2)⇒the maximum value of function 1 is 2.In Function 2: Vertex = (0.5, 4)⇒the maximum value of function 2 is 4.Therefore, Function 2 has a larger maximum.

Anonymous · Answer

We are comparing maxima.  From the graph we know that the max of one graph is +2 at  x = -2.  What about the other graph?  Need to find the vertex to find the max.Complete the square of h(x) = -x^2 + 4x - 2:h(x) = -x^2 + 4x - 2 = -(x^2 - 4x) -2= -(x^2 - 4x + 4 - 4) - 2=-(x^2 - 4x + 4)       -2+4= -(x-2)^2 + 2            The equation describing this parabola is y=-(x-2)^2 + 2, from which we know that the maximum value is 2, reached when x = 2.The 2 graphs have the same max, one at x = -2 and one at x = + 2.

Anonymous

Functions 1 and 2 are shown below: Function 1: f(x) = −4×2 + 6x + 3 ‘A graph of a parabola with x intercepts negative 1, 0 and 1,

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