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What is the charge on the bead?

A 2.10 mm-diameter glass bead is positively charged. The potential difference between a point 2.10 mm from the bead and a point 4.50 mm from the bead is 500 V.

2 Answers

M
Mina Herzog

Feb 20, 2025

The electric potential is proportional to the charge and inversly proportion to the distance:http://en.wikipedia.org/wiki/Electric_potentialThat is:potential at distance r = charge/((4)(pi)k(r))what you know is that V(2.1mm) - V(4.5mm) = 500 VThat is:KQ/2.1 - KQ/4.5 = 500 = KQ (1/(2.1) - 1/(4.5))Since you know K (it is 1/(4(pi)(epsilon-0))) and have a calculator, you should be able to compute Q.... Show More
M
Mina Herzog

Feb 20, 2025

you have to include the radius of the bead. The diameter is 2.1mm then for both r1 and r2 you must add half of that, which is the radius. then you'll get the right answer.... Show More

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