What is the charge on the bead?
A glass bead with a diameter of 2.10 mm carries a positive charge. Given that the potential difference between a point located 2.10 mm from the bead and another point located 4.50 mm from the bead is 500 V, what is the charge on the bead?
2 Answers
The electric potential is proportional to the charge and inversly proportion to the distance:
http://en.wikipedia.org/wiki/Electric_potential
That is:
potential at distance r = charge/((4)(pi)k(r))
what you know is that V(2.1mm) - V(4.5mm) = 500 V
That is:
KQ/2.1 - KQ/4.5 = 500 = KQ (1/(2.1) - 1/(4.5))
Since you know K (it is 1/(4(pi)(epsilon-0))) and have a calculator, you should be able to compute Q.
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