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A

Anonymous

Jan 26, 2025

What is the charge on the bead?

A glass bead with a diameter of 2.10 mm carries a positive charge. Given that the potential difference between a point located 2.10 mm from the bead and another point located 4.50 mm from the bead is 500 V, what is the charge on the bead?

2 Answers

A
Anonymous

Feb 11, 2025

The electric potential is proportional to the charge and inversly proportion to the distance:

http://en.wikipedia.org/wiki/Electric_potential

That is:

potential at distance r = charge/((4)(pi)k(r))

what you know is that V(2.1mm) - V(4.5mm) = 500 V

That is:

KQ/2.1 - KQ/4.5 = 500 = KQ (1/(2.1) - 1/(4.5))

Since you know K (it is 1/(4(pi)(epsilon-0))) and have a calculator, you should be able to compute Q.

A
Anonymous

Jan 16, 2025

you have to include the radius of the bead. The diameter is 2.1mm then for both r1 and r2 you must add half of that, which is the radius. then you'll get the right answer.

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