How much work is done by the horizontal force?

Question

How much work is done by the horizontal force?
A) How much work is done by the horizontal force ( F_p = 150 \, 	ext{N} ) on the 18-kg block shown in the figure when the force pushes the block 4.0 m up a frictionless incline at an angle of 32 degrees?
B) How much work is done by the gravitational force on the block during this displacement?
C) How much work is done by the normal force?
D) What is the speed of the block after this displacement, assuming it starts from rest? [Hint: Consider the work-energy principle, which involves the net work done.]
Any help you can provide would be greatly appreciated. Detailed hints, relevant formulas, and explanations to get me started would be fantastic! Thank you.

Anonymous · Accepted Answer

http://hyperphysics.phy-astr.gsu.edu/hbase/imgmec/...

A)

W = Fp cos 32 * 4 = 150 * 0.848 * 4 = 508.8 J

B)

W = m g sin 32 = 18 * 9.8 * 0.53 * 4 = 373.97 J

C)

Normal force = m g cos 32 + F sin 32 = 18* 9.8 * 0.848 + 150* 0.53 = 229.08 N

This force is perpendicular in the travel and its work W = 0 in the abscence of friction

C1)

F net = F cos 32 - m g sin 32 = 150 * 0.848 - 18 * 9.8 * 0.53 = 127.2 - 93.49 = 33.71N

W = 33.71 * 4 = 134.84 J

D)

Acceleration -- a = Fnet / m = 33.71 / 18 = 1.872 m/s2

Velocity block after 4m

e = 1/2 a t^2 --- t^2 = 2e / a = 8 / 1.872 = 4.27 --- t = √4.27 = 2.0668 s

velocity = a * t = 1.872 * 2.0668 = 3.869 m/s

http://hyperphysics.phy-astr.gsu.edu/hbase/faia.ht...

Goodbye

Anonymous · Answer

for part B answer is Negative make sure that

Mr. Jaylon Kub

How much work is done by the horizontal force?

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